Nuprl Lemma : equiv_rel_subtyping 13,42

T:Type, R:(TTType), Q:(T). EquivRel(T;x,y.R(x,y))  EquivRel({z:TQ(z)} ;x,y.R(x,y)) 
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Uprel 1, rel 1
Definitionst  T, Trans(T;x,y.E(x;y)), Sym(T;x,y.E(x;y)), Refl(T;x,y.E(x;y)), P & Q, x(s), x(s1,s2), EquivRel(T;x,y.E(x;y)), P  Q, , x:AB(x)

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